5x^2+14x=55

Solution for 5x^2+14x=55 equation:

5x^2+14x=55

We move all terms to the left:

5x^2+14x-(55)=0

a = 5; b = 14; c = -55;
Δ = b2-4ac
Δ = 142-4·5·(-55)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-36}{2*5}=\frac{-50}{10}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+36}{2*5}=\frac{22}{10}
=2+1/5
$